What is the difference between a refrigerator and a heat engine?

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SUMMARY

The discussion clarifies the distinction between a refrigerator and a heat engine through the analysis of a thermodynamic cycle involving an ideal monoatomic gas. The process includes an isobaric expansion, an isometric pressure reduction, and an isothermal return to the initial state. The key conclusion is that a negative net work indicates a heat engine, as work is done by the gas, while a refrigerator requires work input to transfer heat from a lower to a higher temperature. Understanding the roles of work and temperature changes is essential for differentiating between these two thermodynamic devices.

PREREQUISITES
  • Understanding of thermodynamic processes: isobaric, isometric, and isothermal.
  • Familiarity with the ideal gas law (PV=nRT).
  • Knowledge of work and heat transfer in thermodynamics.
  • Basic concepts of entropy and its implications in thermodynamic cycles.
NEXT STEPS
  • Study the principles of thermodynamic cycles and their representations on PV diagrams.
  • Learn about the Carnot cycle and its efficiency in heat engines and refrigerators.
  • Explore the concept of entropy and its role in determining the direction of heat transfer.
  • Investigate the mathematical relationships between work, heat, and temperature changes in thermodynamic systems.
USEFUL FOR

Students studying thermodynamics, physics educators, and anyone interested in understanding the fundamental differences between refrigerators and heat engines.

dav2008
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ok..Im doing this review packet for Physics B...I did all of a Thermo problem except one part...

Basically an ideal monoatomic gas first expands in an isobaric process, then the pressure is lowered down isometrically, keeping the volume constant, and finally it is returned to state A isothermally where temperature stays constant...

Part D of the question asks whether this device is a refrigerator or a heat engine... This is what got me confused...I don't even know where to begin...Does it have to do with work being negative or positive?

Part C asked for the net work sign, and i found it was negative(by the new convention at least) because more work was done in the first process (negative, by the gas) than in the third process(positive, on the gas)

..Thanks for any replies..basically i just need to know how to determine if a PV diagram cycle is a refrigirator or a heat engine..tx
 
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OK..i realized it has to do with entropy..but how would i encorporate that with the given information?
 
something I know

Hi,dav2008...
there are something I know after I look through ur questions...the gas frist expands in an isobaric process,it means that the temperature grows up...because PV=nRT,the pressure fixes,but the volumn gets bigger.Q_in=W_out. W_out=nR ln(V_final/V_inital ).

Then the pressure lowered down,and the volumn keep constant, so the temperature also lowered down.W_out=o, Q_in=nC_v T. T---stands for the amount of changed temperature.and C_v=3/2 R, R=8.31J/(mol*K).

Finally, the temperature stays constant,the final temperature lower than the inital.
So I guess the device is refrigerator. I hope those will be useful for u:wink: ! please reply to me if u know the answer...
 
Yea lol..its actually a heat engine.i figured it out with the help of some people...

Since work is negative and done by the gas that means that work is coming out of the system..and in a head engine work is being taken out..Unlike a fridge where work is added


And you are right that the final temperature IS lower than the initial...BUT in a fridge the final temperature is HIGHER than the initial..because u are moving heat from low temperature with the help of work to a higher temperature.
 
hummm...oic...thanks for ur reply...
I always confuse refrigirator and heat engine...
 

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