What is the difference between probability and probability density?

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SUMMARY

The discussion clarifies the distinction between probability and probability density, emphasizing that probability applies to discrete distributions while probability density pertains to continuous distributions. Probability density quantifies the likelihood of an event occurring within a specific interval, as demonstrated by the example of selecting a number from the continuous range [0,1]. The radial distribution function for the hydrogen atom's 1s orbital, represented as P(r) = 4πr²ψ100, illustrates how probability density is utilized in quantum mechanics to describe the likelihood of finding an electron at a given radius.

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ray.deng83
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Like the title, I don't quite understand what probability density is and its difference with probability. Can someone explain a bit on this?
 
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Probability density refers to probably per "area", used to represent probably of an event within a certain interval from a continuous distribution of events. Consider for example an event: randomly picking .50000... from a hat of all real numbers in [0,1]. What's the probability of this event? Zero; 1 in infinity numbers. But what is the probability of picking a number x, such that x<.5000..., from [0,1]. One half, of course. That's a probability density.

So, the radial distribution of the hydrogen atom 1s orbital
P(r) = 4\pi r^{2}\psi_{100}
gives a distribution of probabilties of finding an electron at a radius r. Probability is then
P=\int_{a}^{b}4\pi r^{2}\psi_{100} \,dr
on the radial interval [a,b].
 
Last edited:
blkqi said:
Probability density refers to probably per "area", used to represent probably of an event within a certain interval from a continuous distribution of events. Consider for example an event: randomly picking .50000... from a hat of all real numbers in [0,1]. What's the probability of this event? Zero; 1 in infinity numbers. But what is the probability of picking a number x, such that x<.5000..., from [0,1]. One half, of course. That's a probability density.

So, the radial distribution of the hydrogen atom 1s orbital
P(r) = 4\pi r^{2}\psi_{100}
gives a distribution of probabilties of finding an electron at a radius r. Probability is then
P=\int_{a}^{b}4\pi r^{2}\psi_{100} \,dr
on the radial interval [a,b].

So, probability can be used to describe an event within a discrete distribution which has finite entities and probability density is for an interval in a continuous system. This is because there are infinite entities in a continuous system and any probability of finding a specific one is zero and hence we have to use probability density to describe it.

In this sense, for that example, can we say the probability density of finding a number x, such that 0.3<x<0.5 from [0,1] is (0.5-0.3)/1?
 
ray.deng83 said:
In this sense, for that example, can we say the probability density of finding a number x, such that 0.3<x<0.5 from [0,1] is (0.5-0.3)/1?
Yes, because the distribution of decimals in [0,1] is uniform. In quantum mechanics we commonly deal with non-uniform wavefunctions.
 
Yes and that's why we need those distribution functions. Thanks for your help!
 

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