What is the difference between the equations for Doppler effect and relativity?

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Xeniebop
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Hello, I'm researching about relativity and Doppler effect, most text and book gives the equation for it as

Equation f_o = f_s / (γ(1 + (v cos θ_o)/c)), where γ is the Lorentz factor, showing the relativistic Doppler shift with the observed frequency f_o in terms of source frequency f_s.
(term with square root is on the numerator, and the term w/o is on the denominator)


while on some text, has the reverse of the fraction part (which is the term with the square root is on the numerator

Relativistic Doppler formula: nu prime equals nu times the quantity one minus cos phi times v over c, all divided by the square root of one minus v squared over c squared.


Are they both equal to each other? I can't seem to express/derive the other one from the other one.
Can you explain what are the difference in both equations.

thanks
 
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  • Equation for relativistic Doppler shift: f_o = f_s divided by gamma times (1 + (v cos theta_o)/c), where gamma is the Lorentz factor.
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  • Equation for relativistic Doppler shift: nu prime equals nu times one minus cos phi times v over c, all divided by the square root of one minus v squared over c squared.
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The two expressions differ in how the unit vector giving the direction of the EM wave is defined. Your first formula is for the direction in the source frame, and is used for stellar aberration. Your second formula defines the unit vector in the observer's frame, and is used for the Doppler effect. A good discussion of this is on page 456 of "Classical theory of Electric and Magnetic Fields" by Good and Nelson.