What Is the Displacement of the Centre of Mass When a Man Climbs a Ladder?

[utkarshakash]

Homework Statement

A pulley fixed to a rigid support carries a rope whose one end is tied to a ladder with a man and the other end to a counterweight of mass M. The man of mass m climbs up a distance h with respect to the ladder and then stops. If the mass of the rope and the friction in the pulley axle are negligible, find the displacement of the centre of mass of this system.

Homework Equations

COM$_{y}$=my$_{1}$+my$_{2}$/m+M

The Attempt at a Solution

Let the y-coordinate of man be l and that of mass M be 0. Since it goes up a height h
∴ y-coordinate of the man changes to (l+h) but that of mass M remains unchanged.
So, if I subtract the final COM from initial COM I get the answer mh/m+M. But the correct answer is mh/2M. I'm unable to bring out mistake in my solution.

 

[rl.bhat]

Before man starts climbing the ladder, whether the system is in equilibrium? If yes, you have to take into account the mass of the ladder, which is M- m.

 

[utkarshakash]

Oh, I forgot that the system is in equilibrium. I must have noticed the word counterweight. This is the key to the answer. Thanks so much as now I have arrived at the correct answer.