What Is the Distance Between Adjacent Nodes in Superimposed Waves?

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Homework Help Overview

The discussion revolves around the properties of superimposed traveling waves and the formation of standing waves. The original poster presents two questions: the distance between adjacent nodes in superimposed waves and the wavelength of the original waves given specific node distances in a standing wave scenario.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to understand why adjacent nodes are separated by half a wavelength and seeks clarification on the wavelength in the context of the combined wave. Some participants suggest that the correct formulation of the waves should involve opposite directions to produce a standing wave, noting that nodes occur at points where the amplitude is zero.

Discussion Status

Participants are exploring the definitions and properties of nodes in standing waves, with some providing insights into the relationship between wavelength and node spacing. There is an ongoing inquiry into how to determine the wavelength of the resulting wave from the given information.

Contextual Notes

The original poster expresses confusion regarding the incorporation of distances between nodes and the implications of the wave equations presented. There is also a mention of specific distances between nodes in the context of standing waves that may influence the understanding of wavelength.

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Homework Statement



1)Two Traveling Waves y1=Asin[k(x-ct)] and y2=Asin[k(x-ct)] are superimposed on the same string. What is the distance between adjacent nodes?

2) Standing Waves are produced by the interference of two traveling sinusoidal waves, each of frequency 100 Hz. The distance from the second node to the fifth node is 60 cm. What is the wavelength of the original waves?


Homework Equations


y(x,t)= ymax sin (kx-wt), where w=omega

For the combined wave:

y(x,t)=[2ymax sin kx]cos wt, where w=omega


The Attempt at a Solution



For the first question, I read in my book that adjacent nodes are separated by half a wavelength, but I'm not sure why this is true, and also what is the wavelength in the combined wave in this question? Please help.

For the second question, I know that you find the nodes by equating sin kx to zero, but I'm confused about incorporating the distances?
 
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vivekfan said:

Homework Statement



1)Two Traveling Waves y1=Asin[k(x-ct)] and y2=Asin[k(x-ct)] are superimposed on the same string. What is the distance between adjacent nodes?

2) Standing Waves are produced by the interference of two traveling sinusoidal waves, each of frequency 100 Hz. The distance from the second node to the fifth node is 60 cm. What is the wavelength of the original waves?

I think you ment y1=Asin[k(x-ct)] and y2=Asin[k(x+ct)] because these 2 wave will produce a standing wave once superimposed and this standing wave will have nodes at every half wavelengh. So a node is defined as a fixed point when the amplitude of the wave is 0. Its easy to see if you think about a graph of y=sin(x), This graph will look like the standing wave at any instant in time. So y=0 at x=0, \pi/2 and \pi, the difference between each point is half a wavelength.
 
Easty said:
I think you ment y1=Asin[k(x-ct)] and y2=Asin[k(x+ct)] because these 2 wave will produce a standing wave once superimposed and this standing wave will have nodes at every half wavelengh. So a node is defined as a fixed point when the amplitude of the wave is 0. Its easy to see if you think about a graph of y=sin(x), This graph will look like the standing wave at any instant in time. So y=0 at x=0, \pi/2 and \pi, the difference between each point is half a wavelength.

How do you know what the wavelength of the resulting wave is?
 
The wavelength of each inital wave is the same, so once superimposed the new wave will have the same wavelength, which will be given by ( lambda= 2*pi/k)

So each node will be located at Lambda=pi/k
 

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