Webpage title: Calculating Distance Between Nodes in a Standing Wave on a String

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SUMMARY

The distance between adjacent nodes in a standing wave formed by the superposition of two traveling waves, represented by the equations y1=Asin(ωt−kx) and y2=Asin(ωt+kx), is calculated as π/k. This conclusion is derived from the relationship between the wavelength and the wave number, where the distance between nodes is half the wavelength. The formula for the wavelength is given as λ = 2π/k, leading to the result that the distance between nodes is π/k.

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gleeman
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The question is: "Two traveling waves are superposed on the same string. Waves are y1=Asin (ωt−kx) and y2=Asin(ωt+kx).The distance between adjacent nodes of the resulting standing wave is: "

This is the question I have tried to solve.
I know that the distance between two nodes is 2pii. Then I do not know how to proceed.

The answer is pii/k,
but I do not know how it is obtained.

Please, do not hesitate to reply if you know why the answer is pii/k.

Thank you in advance!
 
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-kx and +kx is the phase shift of the two waves. How far apart are the two waves then? How can you relate this to the period and the distance, x?
 
Thank you, you solved this question as 2pii=2kx => Distance(x)=pii/k.
 

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