What is the drag force on a car traveling at different speeds?

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SUMMARY

The drag force on a car traveling at different speeds can be calculated using the equation D = 0.5 * C_d * ρ * A * v², where C_d is the drag coefficient, ρ is the air density, A is the cross-sectional area, and v is the velocity. For a car measuring 1.6 meters in width and 1.4 meters in height, the calculated drag forces are 68 N at 10 m/s and 615 N at 30 m/s, assuming a drag coefficient (C_d) of 0.5 and an air density (ρ) of 1.22 kg/m³. The confusion arises from using the incorrect formula and values for air density, which should be consistent with the conditions of the problem.

PREREQUISITES
  • Understanding of fluid dynamics principles, specifically drag force calculations.
  • Familiarity with the drag coefficient (C_d) and its impact on drag force.
  • Knowledge of air density values under standard conditions.
  • Ability to manipulate and apply quadratic equations in physics.
NEXT STEPS
  • Research the impact of different drag coefficients (C_d) on vehicle design and performance.
  • Learn how to calculate the cross-sectional area (A) for various vehicle shapes.
  • Explore the effects of air density variations on drag force calculations.
  • Study the principles of terminal velocity and its application to objects in motion.
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Physics students, automotive engineers, and anyone involved in vehicle aerodynamics or performance optimization will benefit from this discussion.

sona1177
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What is the drag force on a 1.6 m wide, 1.4 high car traveling at

A) 10 m/s B) 30 m/s

I'm getting 68 N for part a and 615 N for part B using equation D=.25pAv^2


P= density of air (1.22 kg/m^3) and A is cross sectional area of obect as it faces the wind). *I plugged in 1.22 for p, 2.24 for A, and 30 for v but this is wrong according to the book. What am I doing wrong?

And I don't think I need it to solve this problem but *v terminal = sq rt (4mg/pA).
 
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I don't know how you can solve this problem without knowing the drag coefficient (C_d)for the car. The formula you note is for certain shapes with C_d =0.5; a car could have a greater or lesser C_d depending on its design. (Note: The terminal velocity equation you have noted is for a falling object with a C_d =0.5; it doesn't apply to objects traveling on a level surface.)
 
PhanthomJay said:
I don't know how you can solve this problem without knowing the drag coefficient (C_d)for the car. The formula you note is for certain shapes with C_d =0.5; a car could have a greater or lesser C_d depending on its design. (Note: The terminal velocity equation you have noted is for a falling object with a C_d =0.5; it doesn't apply to objects traveling on a level surface.)

my book says to consider Cd as .5 so I've already included it in the equation. The formula is actually .5CdpAv^2 but my books says Cd is .5 so the equation becomes D=.25pAv^2 so is my answer right? thanks
 
Looks OK to me. Maybe it's a significant figure thing.
 
Thank you kindly for all your help!
 
I'm stuck on the same problem about a car that is 1.6 meter wide and 1.4 meters tall and I have to find the drag force for it at 10 m/s and 30 m/s. But I got the wrong answer when I plugged it into the equation D= .25(rho)(Area)(Velocity^2). I found out that the velocity of Air is 1.29 kg/m^3 and plugged that in for rho but still no luck. Help!
 
rebprice said:
I'm stuck on the same problem about a car that is 1.6 meter wide and 1.4 meters tall and I have to find the drag force for it at 10 m/s and 30 m/s. But I got the wrong answer when I plugged it into the equation D= .25(rho)(Area)(Velocity^2). I found out that the velocity of Air is 1.29 kg/m^3 and plugged that in for rho but still no luck. Help!
Assuming quadratic drag and that Cd/2 = 0.25,, the equation is correct, where rho is the mass density of air. I don't know what the book assumed or gave for the drag coefficient...a mack truck would have a much greater drag cofficient than one of those modern 'bird shaped' vehicles.
 

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