What is the Effective Spring Constant for a System in Series?

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Homework Help Overview

The problem involves two light springs with spring constants k1 and k2 arranged in series, supporting a mass m. Participants are tasked with finding the total extension distance of the springs and the effective spring constant of the system.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss starting points, including drawing force diagrams and deriving equations. There is mention of combining spring constants and the implications of the effective spring constant in a series arrangement.

Discussion Status

Some participants have offered guidance on approaching the problem, with suggestions to focus on the effective spring constant first. There are varying interpretations of the equations involved, and some participants are questioning the correctness of their attempts and the units involved.

Contextual Notes

There is an acknowledgment of potential confusion regarding the equations and units, as well as the need to clarify assumptions about the setup of the springs and the mass.

student 1
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Homework Statement


A light spring with spring constant k1 hangs from a second light spring, which has spring constant K2. An object of mass m hangs at rest from the lower end of the second spring. A. Find the total extension distance of the pair of springs. B. Find the effective spring constant of the pair of springs as a system. We describe these springs as in a series.


Homework Equations

Hooke's Law K=mg/d



The Attempt at a Solution

Where should I start? Would just combine the k's I do not know where to go with this problem?
 
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You should draw out the force diagram and get the force equations from them. You should get 2 equations and they are all you need
 
I'd actually do part B first. They are asking you for k, the spring constant for both springs. If the springs are in series, as a rule, [tex]k = \frac{1}{k1} + \frac{1}{k2}[/tex]. Notice that the resulting k value will be less then both k1 and k2, meaning that the resultant spring will oscillate more then k1 or k2.

Now that you know the k value, you can plug that into hooke's law to get the distance
 
So my D=(mg)(K1K2)/(K1+K2)
 
Hi student 1,

student 1 said:
So my D=(mg)(K1K2)/(K1+K2)

No, that's not quite right. Notice that it does not have the right units (meters on the left, N[itex]^2[/itex]/m on the right).
 
blaaaah i forgot a very important part in the equation i gave you: [tex]\frac{1}{k} = \frac{1}{k1} +\frac{1}{k2}[/tex]. My apologies, student1
 

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