hopeless blonde said:Desperate semi related question. If you have a graph of log intensity against log of (voltage across an LDR in a potential divider circuit)
how do you explain the relationship if your resultant is a straight line of -1.7 obviously in the form of y=mx+c
Log(y)= nlog(x) + logm where y is intensity and x is voltage n being -1.7 and logm being y intercept.
im trying to explain the relationship between the two quantities and ... I am stuck if anyone can help me i would very much appreciate it...
An electric field amplitude is a measure of the strength of an electric field at a specific point in space, usually measured in volts per meter (V/m).
The electric field amplitude is calculated by dividing the force exerted on a unit charge at a specific point in space by the magnitude of the charge. This can be expressed as E = F/q, where E is the electric field amplitude, F is the force, and q is the charge.
The electric field amplitude is inversely proportional to the distance from the source. This means that as the distance from the source increases, the electric field amplitude decreases. This relationship is described by the inverse square law.
The electric field amplitude at a distance of 2m from the source is a specific point of measurement that is commonly used to determine the strength of the electric field. It is also the distance at which the electric field is strongest, as it follows the inverse square law.
The electric field amplitude and electric potential are related by the equation E = -dV/dx, where E is the electric field amplitude and V is the electric potential. This means that the electric field amplitude is the negative gradient of the electric potential, and they both provide information about the strength and direction of the electric field.