What is the electric field magnitude at points where electric potential is zero?

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SUMMARY

The electric field magnitude at points where the electric potential is zero for a system consisting of a -14.3 nC point charge and a +24.9 nC point charge, located 17.4 cm apart on the x-axis, can be determined using the equation for electric potential, V = kq/r. The correct approach involves setting the sum of potentials from both charges to zero, leading to the equation kq1/(r+0.174) + kq2/r = 0. This formulation yields two values for r, one positive and one negative, confirming the existence of two points where the electric potential is zero.

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Homework Statement



A -14.3 nC point charge and a +24.9 nC point charge are 17.4 cm apart on the x-axis. What is the magnitude of the electric field at the two points on the x-axis where the electric potential is zero?

Homework Equations



V = kq/r
E = kq/r^2

The Attempt at a Solution



Since the potential = 0,

q1 = -14.3 nC, q2 = 24.9 nC

kq1/(r+0.174) = kq2/r

But this gives me one negative value for r, whereas I need two values.
 
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Electric potential is a scalar.
 
since net potential is zero then

Potential due to q1 + potential due to q2=0

means equation is

kq1/(r+0.174) + kq2/r = 0 ; {not kq1/(r+0.174) = kq2/r}this will give two values of r one negative and one positive
 
I figured it out, thank you!
 

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