What is the electric potential midway between the two charges?

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SUMMARY

The electric potential midway between two equal positive charges (q=+2.0 µC) separated by 3.0 cm is calculated using the formula V = k(q1 + q2)/r, where k is Coulomb's constant. The distance r is halved to 1.5 cm (or 1.5 x 10^-2 m) for the midpoint calculation. The electric field (E) at this point is derived from the equation E = kq/r^2, confirming that the electric potential and field can be computed using these established formulas. The factor of 2 in the potential equation arises from the contributions of both charges at the midpoint.

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sasuke07
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Homework Statement


Consider two equal positive charges (q=+2.0 µC) a distance of 3.0 cm apart. What is the electric potential midway between the two charges? What is the E field at this point?

I got the work and everything all solved out, i just don't know where some of the numbers came from. Where does the 2 before K come from, I understant the q= 2X10^-6, but why is r 1.5x10^-2? I am just wondering where some of the numbers came from.

Homework Equations


kq/r=E


The Attempt at a Solution


look at attachment
 

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hi sasuke07! :smile:
sasuke07 said:
Where does the 2 before K come from, I understant the q= 2X10^-6, but why is r 1.5x10^-2? I am just wondering where some of the numbers came from.

that equation is kqL/rL + kqL/rL = 2kq/r …

they're defining qR = qL = q and rR = rL = r :wink:

(and r is half of 3.0 cm)
 

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