What is the electrical potential energy of a triangular charge configuration?

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Homework Help Overview

The discussion revolves around deriving and simplifying the expression for the electrical potential energy of a charge configuration arranged in an equilateral triangle with charges +q, -q, and +q.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the approach of calculating potential energy by considering interactions between pairs of charges, drawing parallels to a square configuration. There is uncertainty about the application of trigonometric functions, specifically whether to incorporate sin60 into the expression. Questions arise regarding the nature of electrical potential energy as a scalar quantity.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the potential energy expression. Some guidance has been provided regarding the correctness of the expression if "r" refers to the side of the triangle. However, there is no explicit consensus on the final form of the expression or the role of trigonometric functions.

Contextual Notes

Participants are navigating the complexities of deriving the potential energy in a triangular configuration, with some expressing doubt about the simplicity of their results. There is also a mention of the need for detailed work to clarify misunderstandings.

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Homework Statement


Derive and simplify an expression for the electrical potential energy of the charge configuration. It's an equilateral triangle with charges +q, -q and +q.


Homework Equations


Ep=Kq2/r


The Attempt at a Solution


I know how to do this with squares (it's basically exploding the symmetry). For example in a square there are charges #s1,2,3 and 4. I do the equation with 1 respect to 2,3 and 4. Then with 2 respect to 3 and 4. Finally, 3 respect to 4. I see which terms cancel out, then it's all algebra.

I did this in this triangle, getting -kq2/r as the final expression, which for some reason doesn't convince me (perhaps because it's too simple? lol).

I don't know if in the square you are ''unconsciently'' multiplying by the sin90, therefore I should multiply by sin60 here. If so, is it just multiplying sin60 by each term?

I do know that electrical potential energy is a vector quantity and not a scalar quantity like voltage, right?


Thanks.
 
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so would the expression be -kq2/r *sin60?
 
The potential energy is a scalar quantity. Show your work in detail, please.

ehild
 
Last edited:
stonecoldgen said:

Homework Statement


Derive and simplify an expression for the electrical potential energy of the charge configuration. It's an equilateral triangle with charges +q, -q and +q.


I did this in this triangle, getting -kq2/r as the final expression, which for some reason doesn't convince me (perhaps because it's too simple? lol).

It is correct if you mean the side of the triangle by "r".

ehild
 

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