What is the electron mobility of copper?

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    Electron Mobility
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SUMMARY

The electron mobility of copper can be calculated using the relationship σ = nqμ, where σ is the electrical conductivity (5.96 x 10^7 S/m), n is the number density of electrons, and μ is the mobility. The charge of the electron is 1.60 x 10^-19 coulombs, and the density of copper is 8.92 g/cm^3. After performing the calculations, the mobility was determined to be 68.61 cm²/V·s, based on a calculated electron density of 8.195 x 10^22 electrons/cm³.

PREREQUISITES
  • Understanding of electrical conductivity and its units (S/m)
  • Knowledge of electron charge (1.60 x 10^-19 C)
  • Familiarity with density calculations and unit conversions
  • Basic grasp of the relationship between mobility, conductivity, and electron density
NEXT STEPS
  • Learn about SI and cgs unit systems for consistent calculations
  • Study the derivation and applications of the formula σ = nqμ
  • Explore the concept of electron density in different materials
  • Investigate the impact of temperature on electron mobility in metals
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Students in electronics and physics courses, electrical engineers, and anyone interested in semiconductor properties and material conductivity.

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The electrical conductivity of copper is 5.96 x 10^7 S/m; its atomic weight is
65.546 AMU; the charge on the electron is 1.06 x 10-19 coulombs; the density of
copper is 8.92 g/cm^3. Assume there is one free electron per copper atom. Calculate
the mobility in cm^2/volt-sec.

This is a question from my electronics lab course and i am not sure how to even start with it.
This problem probably isn't that difficult but i have no idea what equations to use since my prof
thinks that everyone knows much more than they do and rarely tells us what equations to use.
Any help with this would be really appreciated.
 
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Anyone willing to help?
 
I'm learning this alongside with you:

<< There is a simple relation between mobility and electrical conductivity. Let σ = conductivity, n = number density of electrons, and μ = mobility. Then

σ = nqμ.

This formula is valid when the conductivity is due entirely to electrons. >>

http://en.wikipedia.org/wiki/Electron_mobility
 
rude man said:
I'm learning this alongside with you:

<< There is a simple relation between mobility and electrical conductivity. Let σ = conductivity, n = number density of electrons, and μ = mobility. Then

σ = nqμ.

This formula is valid when the conductivity is due entirely to electrons. >>

http://en.wikipedia.org/wiki/Electron_mobility


So i did the calculations and got 68.61 cm^2/V s, is that correct?
 
Didn't do them myself. What were your σ, n and q?
 
rude man said:
Didn't do them myself. What were your σ, n and q?

σ and q are in the question and i calculated n by converting the density of copper to the density of electrons and got 8.195 x 10^22 electrons/cm^3
 
We got problems.

Starting with the charge of the electron not being 1.06e-19 but 1.60e-19 C.

Then, you're mixing units. You must express all quantities in one consistent system of units. Personally I'm an SI man but there are others, e.g. the cgs system the wacko theoretical types prefer :-). Grams and cm are cgs, but the conductivity is given in S/m which is SI. I suggest you convert to SI for everything. Mainly because if I am to check your calculations I want to do it in SI. Cgs makes me nervous.

n is number of Cu atoms per m^3. Convert amu of 1 Cu atom to kg, then knowing the density of Cu you can compute the number of Cu atoms in 1 m^3 volume = n.
 

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