What is the Density of Conduction Electrons in Monovalent Copper?

[teme92]

Homework Statement

Monovalent copper (one conduction electron per atom) has a density of 9000 kg m^-3 and atomic mass of 64 amu (ie. 1 kmole = 64kg). Find:

a)The density of conduction electrons per unit volume

b)the Fermi energy in electron volts

Homework Equations

f(E) = 1/(e^(E-E_F)/KT+1)

ρ=m/V

The Attempt at a Solution

So this is the first problem I've done on Fermi-Dirac so I'm a bit stuck here.

So I got the volume from V=m/ρ, so:

V=64/9000=.007m³

Is this even relevant to the question? Really lost and any help would be much appreciated

 

[teme92]

I think I have to use the formula n=DN_A/m

where:

N_A=Avogadros No. = 6.02x10²³ mol^-1
D=Density=9000 kg m^-3=9000000 g m^-3
m=64 amu= g mol^-1

I used the formula to get n=(9000000)(6.02x10²³)/64=8.4375x10²⁸ m^-3

Is this the answer for part a)?