- #1

november1992

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## Homework Statement

A 3 m long copper wire that has a diameter of 6 mm is connected to a 9 V battery.

a) What is the current through the wire?

b) If wire a was connected to a battery for 1 second, how much energy would the wire dissipate?

## Homework Equations

A = [itex]\pi[/itex][itex]r^{2}[/itex]

R = [itex]\rho[/itex][itex]\frac{L}{A}[/itex]

i = [itex]\frac{V}{R}[/itex]

[itex]\rho[/itex] = 1.72 x [itex]10^{-8}[/itex]

P = i * V

W = P * t

## The Attempt at a Solution

I got:

R = 1.82mΩ

i = 4945 A

p = 44505.45

I'm unsure of my answers. The values seem to be too high.

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