(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

2. Relevant equations

P = I*V energy dissipated = wr = ∫ ( P *dt) .... t is from 0 to .4 seconds vs = 400t^2 = 400 * (.4^2) = 64 V

3. The attempt at a solution

Using KVL I said Vs ( 64 V) = 100 * i .... I found that I was 64/100 = .64 amps. I then said power is .64 amps ^ 2 * 100 ohms = 40.96 Watts. I then integrated 40.96 Watts with respects to time ... Energy dissipated = wr = ∫ ( 40.96 Watts *dt ) from 0 to .4 seconds = 40.96 * .4 = 16.384 J.

Where did I go wrong?

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# Homework Help: Energy dissipated in a resistor during a time interval?

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