What is the Equation for Calculating Halley's Comet Eccentricity?

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    Comet Eccentricity
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SUMMARY

The eccentricity of Halley's Comet is calculated using the formula Rp = a(1 - e), where Rp is the periapsis distance and a is the semi-major axis. Given that the periapsis distance (Rp) is 0.6 AU, and the orbital period is 76 years, the semi-major axis can be derived from Kepler's Third Law. The eccentricity of Halley's Comet is established at 0.967, confirming its highly elliptical orbit.

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  • Understanding of orbital mechanics and Kepler's laws
  • Familiarity with the concepts of periapsis and semi-major axis
  • Basic algebra for solving equations
  • Knowledge of astronomical units (AU) and their significance
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  • Study Kepler's Third Law of planetary motion
  • Learn how to calculate the semi-major axis from orbital period
  • Explore the implications of eccentricity in celestial mechanics
  • Investigate other comets and their orbital characteristics
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Astronomy students, astrophysicists, and anyone interested in celestial mechanics and the dynamics of cometary orbits.

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Homework Statement


I am given Rp=.6AU and need to find the eccentricity.


Homework Equations


Rp=a(1-e)


The Attempt at a Solution


I can find what Halley's comet eccentricity is (0.967) but I need to actually calculate it. What is the equation I need? I know I need to know Ra, or a, or p.
 
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Are you told the period of Haley's orbit?
 
gabbagabbahey said:
Are you told the period of Haley's orbit?

yes, I guess I was and overlooked it. It was stated in 1910-1986, so 76 years. I can now find a and solve the problem. Thanks!
 

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