What is the explicit representation of 2cos(omega)t - 1/4 sin(omega)t = 0?

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SUMMARY

The explicit representation of the equation 2cos(ωt) - 1/4sin(ωt) = 0 can be derived by isolating the trigonometric functions. By rearranging the equation, it becomes clear that (1/4)sin(ωt) = 2cos(ωt), leading to the conclusion that tan(ωt) = 8. This indicates that ωt must equal arctan(8) plus any integer multiple of π to satisfy the equation. The discussion emphasizes the importance of understanding the relationship between sine and cosine functions in solving trigonometric equations.

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explicit representation??

I got to show the explicit representation of 2cos(omega)t - 1/4 sin(omega)t = 0. what is this? is this operator notation??
 
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I have no idea what you mean by "explicit repesentation". Obviously [itex]2cos(\omega t)- (1/4)sin(\omega t)= 0[/itex] is only true for some values of t.
Specifically, if [itex]2cos(\omega t)- (1/4)sin(\omega t)= 0[/itex] , then [itex](1/4)sin(\omega t)= 2 cos(\omega t)[/itex] and [itex]sin(\omega t)/cos(\omega t)= tan(\omega t)= 8[/itex]. You could use a calculator to see what [itex]\omega t[/itex] must equal.
Where did you see that? What was the context?
 

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