What Is the Fake Gravity on a Circular Space Hotel Orbiting Earth?

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SUMMARY

A circular space hotel orbiting Earth with a radius of 220 meters can achieve a centripetal acceleration of 9.81 m/s² by rotating at a tangential speed of 46.456 m/s. The corresponding angular velocity for this setup is 0.211 radians per second. For a point located 77 meters below the outer rim, the new radius is 143 meters, which affects the experienced acceleration. The equation ac = rω² is applicable for calculating the centripetal acceleration at different radii within the space station.

PREREQUISITES
  • Understanding of centripetal acceleration and its formula
  • Familiarity with angular velocity and its relationship to tangential speed
  • Knowledge of basic physics equations related to circular motion
  • Ability to perform calculations involving square roots and radians
NEXT STEPS
  • Study the derivation and applications of the centripetal acceleration formula
  • Learn about the effects of varying radius on perceived gravity in rotating systems
  • Explore the concept of angular momentum and its relevance in circular motion
  • Investigate real-world applications of artificial gravity in space habitats
USEFUL FOR

Students studying physics, aerospace engineers, and anyone interested in the dynamics of rotating space habitats and artificial gravity systems.

anthonyslvtr
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Homework Statement



A circular space hotel in orbit around the Earth has a radius of 220m. in order to produce "fake gravity" along the outer rim, it is desired to rotate at a speed that will produce a centripetal acceleration of 9.81 m/s^2.
A) find the tangential speed of appoint on the rim when the station is producing the required centripetal acceleration.
B) Find the station's angular velocity under those conditions, in radians per second.
C) If you're "below deck" at a point 77m from the outer rim, how much "gravity" will you experience?
D) If you start moving from the rim toward the central hub of the space station, what will it feel like? How will your perception change as you move?

Homework Equations



vt = √(ac*r)
ῳ = v/r

The Attempt at a Solution



A) I interpreted the following: ac = 9.81m/s^2 and r= 220m. With these I plugged into the first equation to find the tangential velocity which came out to be vt=46.456m/s.

B) To find the angular velocity I plugged in the vt and r in the second relevant equation and found ῳ=0.211rad/s.

C) Assuming I did the first two parts correctly (let me know if I did not please), this is what's giving me a problem. If 77 m "below deck" that would give you a new radius of 143m. I believe this would change your ac or completely eliminate it. Would the following equation work: ac = rῳ2?
I'm open to discuss this back and forth rather than just asking for help or an answer.
 
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anthonyslvtr said:
Would the following equation work: ac = rῳ2?
Yes.
 

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