What is the final temperature of an isentropic expansion with a given function?

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In an isentropic expansion, the entropy change (ds) is zero, which simplifies the analysis of the system. The user is tasked with determining the final temperature after the pressure is halved, starting from an initial temperature (T0) and pressure (P0). They consider the relationship between internal energy (u), temperature (T), and pressure (P) while exploring how volume changes during the process. The discussion highlights the need to express temperature and pressure in terms of derivatives of internal energy with respect to entropy and volume. Ultimately, the user seeks a method to relate the final temperature to the initial temperature without specific values.
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Homework Statement



I have a system u =Av-2exp(s/R)

N moles of this substance initially at T0 and P0 are expanded isentropically until the pressure is halved. What is the final temperature?

Homework Equations



du = \partialu\partials ds + \partialu\partialv dv
du = Tds - Pdv


The Attempt at a Solution



If this function is changing isentropically, ds would have to be zero, correct? The derivative of v would have to be such as to multiply P times 1/2, correct? But, if ds --> zero, how do I find my final temperature as a multiple of my initial temperature? Do I have to start plugging values which would satisfy these conditions back into the original equation?
 
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How about expressing T as (\partial U/\partial S)_V and P as -(\partial U/\partial V)_S and looking at how the volume changes during the process?
 

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