What is the Force Ranking in an Elevator with Stacked Blocks?

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SUMMARY

The discussion centers on the ranking of forces acting on three stacked blocks (1kg, 2kg, and 3kg) in a stationary elevator. Participants analyze the forces according to Newton's Laws, specifically focusing on the interactions between the blocks and the elevator floor. The correct ranking from largest to smallest force is: the force of the floor on the 1kg block (largest), followed by the forces between the blocks: F of 3 on 2 and F of 2 on 3 (equal), and finally F of 1 on 2 and F of 2 on 1 (equal). Understanding these relationships is crucial for solving similar physics problems.

PREREQUISITES
  • Newton's Laws of Motion
  • Understanding of forces and their interactions
  • Basic concepts of mass and weight
  • Knowledge of normal force and action-reaction pairs
NEXT STEPS
  • Study the application of Newton's Third Law in various contexts
  • Learn about normal force calculations in static systems
  • Explore examples of force diagrams in physics problems
  • Investigate the effects of acceleration on force rankings in dynamic systems
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, educators teaching Newton's Laws, and anyone interested in understanding force interactions in static systems.

iluvphys
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Hello guys, I am currently busy with this introductory assignment on Newtons Laws.
I have tried to solve but i am not sure whether i have the right solution.
Please help.

Homework Statement



Three blocks are stacked on top of each other inside an elevator as shown in the figure.
Answer the following questions with reference to the eight forces defined as follows.

the force of the 3kg block on the 2kg block, F of 3 on 2,
the force of the 2kg block on the 3kg block, F of 2 on 3,
the force of the 3kg block on the 1kg block, F of 3 on 1,
the force of the 1kg block on the 3kg block, F of 1 on 3,
the force of the 2kg block on the 1kg block, F of 2 on 1,
the force of the 1kg block on the 2kg block, F of 1 on 2,
the force of the 1kg block on the floor, F of 1 on floor, and
the force of the floor on the 1kg block, F of floor on 1.

Assume the elevator is at rest. Rank the magnitude of the forces.
Rank from largest to smallest.

3kg block
V
2kg block
V
1kg block
v
elevator floor


The Attempt at a Solution



F of floor on 1 and F 1 on floor (equal), F of 3 on 2 and F of 2 on 3 (equal), F of 2 on 1 and F of 1 on 2 (equal), F of 3 on 1 and F of 1 on 3 (equal).

Is this ranking right? Thanks
 
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Hi iluvphys,

iluvphys said:
Hello guys, I am currently busy with this introductory assignment on Newtons Laws.
I have tried to solve but i am not sure whether i have the right solution.
Please help.

Homework Statement



Three blocks are stacked on top of each other inside an elevator as shown in the figure.
Answer the following questions with reference to the eight forces defined as follows.

the force of the 3kg block on the 2kg block, F of 3 on 2,
the force of the 2kg block on the 3kg block, F of 2 on 3,
the force of the 3kg block on the 1kg block, F of 3 on 1,
the force of the 1kg block on the 3kg block, F of 1 on 3,
the force of the 2kg block on the 1kg block, F of 2 on 1,
the force of the 1kg block on the 2kg block, F of 1 on 2,
the force of the 1kg block on the floor, F of 1 on floor, and
the force of the floor on the 1kg block, F of floor on 1.

Assume the elevator is at rest. Rank the magnitude of the forces.
Rank from largest to smallest.

3kg block
V
2kg block
V
1kg block
v
elevator floor


The Attempt at a Solution



F of floor on 1 and F 1 on floor (equal), F of 3 on 2 and F of 2 on 3 (equal), F of 2 on 1 and F of 1 on 2 (equal), F of 3 on 1 and F of 1 on 3 (equal).

Is this ranking right? Thanks

I don't believe these are quite right. The ones you have identified as equal are equal, but there is one grouping out of place. How did you decide on the relative strengths?
 
Good morning alphysicist,
a)well I started thinking that most of the weight is on the 1kg block therefore the force that it puts on the floor must be equal to what the floor puts back on the block (N´s 3rd law).
b)However i wasnt really sure about the last one since I believed that the 3kg block doesn't directly put its force on the 1kg block,it is rather the force of block3 and the force of block 2 acting on the 1kg block.

Could you please tell me where my mistake is? Thank you
 
iluvphys said:
Good morning alphysicist,
a)well I started thinking that most of the weight is on the 1kg block therefore the force that it puts on the floor must be equal to what the floor puts back on the block (N´s 3rd law).
b)However i wasnt really sure about the last one since I believed that the 3kg block doesn't directly put its force on the 1kg block,it is rather the force of block3 and the force of block 2 acting on the 1kg block.

Those both sound right to me. It's the forces in the middle that I am thinking about.

Think about what each block is supporting. For example, the floor is supporting all three blocks (6kg of mass), so the floors force on the 1 kg mass is the largest force (and equal to the 1kg mass's reaction force on the floor).

Now think about what the 1kg mass is supporting and what the 2kg mass is supporting. Do you see what's wrong?
 
Oh you´re right.
I wasn´t really considering the two in the middle they seemed not really "important" in the beginning. But now i understand that Block 1 has a bigger impact on block 2 than block 3 has on 2, and the other way round!
Well, thanks again.
 
iluvphys said:
Oh you´re right.
I wasn´t really considering the two in the middle they seemed not really "important" in the beginning. But now i understand that Block 1 has a bigger impact on block 2 than block 3 has on 2, and the other way round!
Well, thanks again.


That's right, because the upward normal force from block 1 is supporting both blocks 2 and 3, while the upward normal force from block 2 is only supporting block 3.

Glad to help!
 

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