What is the Formula for Calculating Doppler Effect in a Moving Train Scenario?

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SUMMARY

The Doppler Effect formula for calculating the frequency detected by a stationary observer and a moving observer in a train scenario is given by F = F' * (V +/- Vd)/(V +/- Vs). In this case, F' is the emitted frequency of 295 Hz, V is the speed of sound, Vd is the speed of the detector, and Vs is the speed of the source, which is the train moving at 29 m/s. The correct application of the formula requires understanding the signs based on the relative motion of the source and the observer.

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Homework Statement


A train moving toward a detector at 29 m/s blows a 295-Hz whistle. What frequency is detected on each of the following?
(a) a stationary train
(b) a train moving toward the first train at 21 m/s

Homework Equations


V = f * Wavelength
(f = frequency, V = velocity in m/s)

T = 1/f
(T= period in sec.)

The Attempt at a Solution


1. i know the doppler's effect is involved here somehow, and that it has to do with frequency increasing as the space between the two objects (one emitting the waves) grows smaller. but my teacher never gave us any sort of formula for this scenario, and i just absolutely have no idea how to approach this problem or determine by how much the frequency increases given just velocity & frequency. please help..Any or all help appreciated...I apologize for my lack of knowledge. I really was never good at physics or anything math related...

Thanks.
 
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The formula needed is F = F' * (V +/- Vd)/(V +/- Vs) where F is the frequency observed, F' is the frequency emitted, V is the speed of sound, Vd is the speed of the detector and Vs is the speed of the source. You have to determine the signs based on your knowledge of how sound works.
 

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