What is the formula for error analysis in multiplication and division?

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SUMMARY

The forum discussion focuses on error analysis in multiplication and division, specifically addressing how to calculate errors when given values with uncertainties. The key takeaway is that for multiplication and division, the new error is determined using relative errors, calculated as the absolute error divided by the value. The example provided demonstrates that for x=3±2 and y=5±3, the results yield x*y=15±13.45 and x/y=0.6±0.538. This method emphasizes the importance of switching between absolute and relative errors for accurate calculations.

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  • Understanding of absolute and relative errors
  • Familiarity with basic arithmetic operations (multiplication and division)
  • Knowledge of error propagation techniques
  • Basic statistics concepts, particularly regarding means and standard deviations
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This discussion is beneficial for students in scientific fields, particularly those involved in laboratory work, as well as educators teaching error analysis in mathematics and physics. It is also useful for anyone needing to understand the implications of measurement uncertainties in calculations.

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Homework Statement


hi there i am currently working on a lab report which involves intense error anaylsis and i stink at it so i have made up the following two questions to understand how to perform error analysis with multiplication and division

if x=3+-2 m y=5+-3 s

then what is x*y answer in the form a+-b where a is the mean and b is the error

and also what is x/y in the form a+-b where a is the mean and b is the error

please help!


Homework Equations





The Attempt at a Solution

 
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Hi, the basic rules for error analysis are that for addition and subtraction working with absoulte errors ie plus or minus 1cm would be an example of an absolute error, you just add or subtract the values, and the new error in both cases is given by the square root of the sum of the squares of the absoute errors. ie sqrt[(error in a)^2 + (error in b)^2]



For multiplication or division, you just multiply or divide the values and the new error is given by the same formula but instead of using absolute errors, use relative errors, ie percentage errors, so depending on what sort of errors you have to start with you may just have a bit of switching between absolute and relative errors where

relative error = (absolute error)/value

so considering the values you gave

x*y = 3*5 +- sqrt[(2/3)^2+(3/5)^2)*3*5 = 15+-sqrt(181/225)*15 = 15 +-13.45

and x/y= 3/5 +- sqrt[(2/3)^2+(3/5)^2)*3/5 = 0.6 +- 0.538

Hope this helps
 

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