Joza Messages 139 Reaction score 0 Thread starter May 29, 2007 #1 IS there a formula for: z=(Cosx +iSinx)^4 (Cosy + iSiny)^2 ??
daveb Messages 548 Reaction score 2 May 29, 2007 #2 You mean a way to simplify it? Just change each expression in ( ) to its corresponding exponential form.
You mean a way to simplify it? Just change each expression in ( ) to its corresponding exponential form.
Werg22 Messages 1,431 Reaction score 1 May 29, 2007 #3 This doesn't make any sense: one of x and y has to represent the real part scalar and the other the imaginary part scalar. The expression you have there implies that neither x nor y are scalars and hence aren't axial values. Last edited: May 29, 2007
This doesn't make any sense: one of x and y has to represent the real part scalar and the other the imaginary part scalar. The expression you have there implies that neither x nor y are scalars and hence aren't axial values.
Joza Messages 139 Reaction score 0 May 29, 2007 #4 Well I just put them in instead of the actual values...I'm just looking for the general way. So do I simplify each and then multiply them or something?
Well I just put them in instead of the actual values...I'm just looking for the general way. So do I simplify each and then multiply them or something?
Werg22 Messages 1,431 Reaction score 1 May 29, 2007 #5 If so, have you tried, as daveb suggested[tex]z=(\cos x +i\sin x)^{4} * (\cos y + i\sin y)^{2}[/tex] [tex]z = e^{4xi} * e^{2yi}[/tex] [tex]z = e^{(4x + 2y)i}[/tex] [tex]z = \cos (4x + 2y) + i \sin (4x + 2y)[/tex] Last edited: May 29, 2007
If so, have you tried, as daveb suggested[tex]z=(\cos x +i\sin x)^{4} * (\cos y + i\sin y)^{2}[/tex] [tex]z = e^{4xi} * e^{2yi}[/tex] [tex]z = e^{(4x + 2y)i}[/tex] [tex]z = \cos (4x + 2y) + i \sin (4x + 2y)[/tex]
Joza Messages 139 Reaction score 0 May 29, 2007 #6 I have only ever seen the last line there before, but that's actually what I thought it was. It's one of those rules. Cheers guys!
I have only ever seen the last line there before, but that's actually what I thought it was. It's one of those rules. Cheers guys!