What is the Formula for Multiplying Complex Numbers in Polar Form?

Joza
Messages
139
Reaction score
0
IS there a formula for:

z=(Cosx +iSinx)^4 (Cosy + iSiny)^2 ??
 
on Phys.org
You mean a way to simplify it? Just change each expression in ( ) to its corresponding exponential form.
 
This doesn't make any sense: one of x and y has to represent the real part scalar and the other the imaginary part scalar. The expression you have there implies that neither x nor y are scalars and hence aren't axial values.
 
Last edited:
Well I just put them in instead of the actual values...I'm just looking for the general way.

So do I simplify each and then multiply them or something?
 
If so, have you tried, as daveb suggested[tex]z=(\cos x +i\sin x)^{4} * (\cos y + i\sin y)^{2}[/tex]

[tex]z = e^{4xi} * e^{2yi}[/tex]

[tex]z = e^{(4x + 2y)i}[/tex]

[tex]z = \cos (4x + 2y) + i \sin (4x + 2y)[/tex]
 
Last edited:
I have only ever seen the last line there before, but that's actually what I thought it was. It's one of those rules.

Cheers guys!
 

Similar threads

  • · Replies 15 ·
Replies
15
Views
4K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 12 ·
Replies
12
Views
45K
  • · Replies 19 ·
Replies
19
Views
4K