What is the Fourier Transform of f(-x)?

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SUMMARY

The Fourier Transform of the function f(-x) can be derived using the properties of even and odd functions. If f(-x) is even, then it simplifies to f(x), while if f(-x) is odd, it becomes -f(x). The general equation for the Fourier Transform is expressed as F(f(-x)) = ∫ f(-x) e^(-i2πft) dt. Understanding these properties is crucial for correctly applying the Fourier Transform to functions defined over symmetric intervals.

PREREQUISITES
  • Understanding of Fourier Transform fundamentals
  • Knowledge of even and odd functions
  • Familiarity with complex exponentials
  • Basic calculus, particularly integration techniques
NEXT STEPS
  • Study the properties of even and odd functions in Fourier analysis
  • Learn about the application of the Fourier Transform in signal processing
  • Explore the derivation of the Fourier Transform for various types of functions
  • Investigate the role of complex exponentials in Fourier Transforms
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Students and professionals in mathematics, physics, and engineering who are studying signal processing or analyzing functions using Fourier analysis.

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Homework Statement


Find the Fourier transform of f(-x)


Homework Equations





The Attempt at a Solution


The way I tried to solve is
Fourier series is a sum of even and odd functions.
If f(-x) is even then, f(-x)=f(x)
If f(-x) is odd then, f(-x)= -f(x)

Sum of even and odd function is neither even nor odd.
I am lost after this. Any help?
 
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Can you write the general equation for finding a Fourier transform? Saying it is the "sum of even and odd functions" is pretty general. I've usually seen the transform as an integral containing a complex exponential or sines and cosines.
 
ok.
F(f(-x)) = int( f(-x) e^-i2pift dt)
Not sure how to solve this.
 

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