Fourier/heat problem involving hyperbolic sine

In summary, the rectangular box with walls at temperature T1, except for the wall at z=c which is held at temperature T2, reaches equilibrium with the temperature function T(x,y,z) satisfying ∂T/∂t =D∇2T. The temperature in the box can be represented as T(x,y,z) = T1 + τ(x,y,z), where τ is the Fourier series τ(x,y,z)=∑∑anmsin(nπx/a)sin(mπy/b)f(z). The "tau" function τ(x,y,z) satisfies the partial differential equation ∂T/∂t =D∇2T under equilibrium conditions. This leads to the conclusion that f(z)
  • #1
danmel413
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0

Homework Statement


A rectangular box measuring a x b x c has all its walls at temperature T1 except for the one at z=c which is held at temperature T2. When the box comes to equilibrium, the temperature function T(x,y,z) satisfies ∂T/∂t =D∇2T with the time derivative on the left equal to zero. Find the temperature T in the box in the form T(x,y,z) = T1 + τ(x,y,z) where τ is the Fourier series τ(x,y,z)=∑∑anmsin(nπx/a)sin(mπy/b)f(z).

Find f(z) and find anm

Homework Equations


D=kA/mc
All others listed in the question

The Attempt at a Solution


so I see that it's sin functions in x and y in the Fourier series because there are zero's at 0 and a, b for both. However since there's only one 0 for z at z=0, I'm assuming that f(z) has to be sinh. But I don't think I can just take the argument there to be jπz/c.

If someone can bump me forward I'm sure I can figure the rest of the question out.
 
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  • #2
What partial differential equation must τ(x,y,z) satisfy?
 
  • #3
TSny said:
What partial differential equation must τ(x,y,z) satisfy?

T(x,y,z) satisfies ∂T/∂t =D∇2T and T(x,y,z) = T1 + τ(x,y,z)
 
  • #4
danmel413 said:
T(x,y,z) satisfies ∂T/∂t =D∇2T and T(x,y,z) = T1 + τ(x,y,z)
What differential equation does the "tau" function τ(x,y,z) satisfy under equilibrium conditions?
Use this to determine the form of f(z).
 
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