What is the Fourier Transform of sin?

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Homework Help Overview

The discussion revolves around finding the Fourier transform of the sine function, specifically within the interval from -π to π. Participants are exploring the implications of changing the limits of integration and the relationship to the Dirac delta function.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are questioning the necessity of the Dirac delta function in the Fourier transform of sin(t) and discussing the appropriateness of integrating over the interval from -π to π versus -∞ to ∞.

Discussion Status

There is an ongoing exploration of the correct limits for the Fourier transform integral, with some participants clarifying the setup of the function being transformed. Guidance has been offered regarding the validity of integrating from -π to π based on the function's definition.

Contextual Notes

Participants are navigating the constraints of the problem, particularly the definition of the function and the limits of integration, which are central to the discussion.

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Homework Statement



Hey guys.
I need to find the Fourier transform of sin, is this right?

http://img156.imageshack.us/img156/5531/scan0004r.jpg

I searched the internet but all I could find is the answer with the dirac delta and I don't need that.

Thanks.


Homework Equations





The Attempt at a Solution

 
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The Fourier transform of sin(t) involves the Dirac delta function. What do you mean by "I don't need that"? And why did you change the limits from -∞ to ∞ to -π to π in your integral?
 
dx said:
The Fourier transform of sin(t) involves the Dirac delta function. What do you mean by "I don't need that"? And why did you change the limits from -∞ to ∞ to -π to π in your integral?

Oh, sorry, I need to find it from -pi to pi.
Is there something wrong with what I did?

Thanks.
 
I didn't read your whole solution, but there is a mistake in your first step. The Fourier transform integral goes from -∞ to ∞. Why did you change those limits?
 
dx said:
I didn't read your whole solution, but there is a mistake in your first step. The Fourier transform integral goes from -∞ to ∞. Why did you change those limits?

Yeah, I need to find it from -pi to pi.
Is that way it doesn't involves Dirac function?

Thanks.
 
No! It's not from -pi to pi. It's -∞ to ∞.
 
dx said:
No! It's not from -pi to pi. It's -∞ to ∞.

:smile:

But that is the question.
Find Fourier transform of sin in -pi<t<pi.

What do you mean?

Thanks.
 
Your question is to transform the function [tex]f(t) = \left\{ \begin{matrix} \sin t & \mathrm{if}\; -\pi < t < \pi \\ 0 & \mathrm{otherwise} \end{matrix} \right[/tex] ?
 
Cyosis said:
Your question is to transform the function [tex]f(t) = \left\{ \begin{matrix} \sin t & \mathrm{if} -\pi < t < \pi \\ 0 & \mathrm{otherwise} \end{matrix} \right[/tex] ?

Yeah, sorry for the misconfusion.
 
  • #10
Then your approach is correct since the function is zero outside -pi<t<pi anyway so you may as well integrate from -pi to pi.
 
  • #11
Ah, now it makes sense! Thanks Cyosis!
 
  • #12
You're welcome.
 

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