What is the frequency of a tuning fork oscillating at 2770 rad/s?

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SUMMARY

The frequency of a tuning fork oscillating at 2770 rad/s can be calculated using the formula f = ω / (2π), resulting in approximately 441.5 Hz. This tuning fork, described by the equation x = 0.00150cos(2770t), exhibits simple harmonic motion. The increased loudness when held above a glass bottle full of milk is likely due to resonance, where the natural frequency of the bottle amplifies the sound produced by the fork.

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Timiop2008
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A tuning fork oscillates with simple harmonic motion described the equation:

x = 0.00150cos(2770t) (where t is seconds)

a) calculate the frequency in Hz of the tuning fork

b) Suggest why only this tuning fork (taken from a set of 10 forks) gets louder when held above a glass bottle full of milk.

I don't know how to go about this question. Any help greatly appreciated.
 
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Timiop2008 said:
A tuning fork oscillates with simple harmonic motion described the equation:

x = 0.00150cos(2770t) (where t is seconds)

a) calculate the frequency in Hz of the tuning fork

b) Suggest why only this tuning fork (taken from a set of 10 forks) gets louder when held above a glass bottle full of milk.

I don't know how to go about this question. Any help greatly appreciated.
A look at http://en.wikipedia.org/wiki/Simple_harmonic_motion, especially at the first formula encountered, will give you the straightforward answer.
 

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