What is the frequency of the tuning fork?

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SUMMARY

The frequency of the tuning fork can be calculated using the formula f = mv/2L, where v is the speed of sound in air (343 m/s) and L is the effective length of the tube. The total lengths at which standing waves occur are 42.5 cm, 56.7 cm, and 70.9 cm. The calculations indicate that the frequency of the tuning fork is approximately 214.375 Hz when using an effective length of 80 cm (0.8 m). The standing wave conditions confirm that the tube resonates at these specific lengths, which correspond to half wavelengths.

PREREQUISITES
  • Understanding of wave mechanics and standing waves
  • Familiarity with the speed of sound in air at 20 degrees Celsius
  • Knowledge of the relationship between frequency, wavelength, and tube length
  • Basic algebra for manipulating equations
NEXT STEPS
  • Research the principles of standing waves in open tubes
  • Learn about the speed of sound variations with temperature
  • Explore the concept of harmonics and their relation to tube length
  • Study the effects of tube diameter on resonance frequencies
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Students studying physics, particularly those focusing on wave mechanics, acoustics, and sound resonance in tubes.

rayhan619
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Homework Statement



A 40 cm long tube has 40 cm long insert that can be pulled in and out. A vibrating tuning fork is held next to the tube. as the insert is slowly pulled out the sound from the tuning fork creates standing waves in the tube when the total length is 42.5 cm, 56.7 cm, and 70.9 cm. what is the frequency of the tuning fork? The air temperature is 20 degree C.

Homework Equations



f = mv/2L

figure is attached

The Attempt at a Solution



f = 14.2
v = 343 m/s
L =(40+40) cm = 80 cm = 0.8 m

f = mv/2L = (1*343 m/s)/2*0.8 m = 214. 375 hz

got it wrong. not sure how to do it
 

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total length is 42.5 cm, 56.7 cm, and 70.9 cm.
These values indicate that the open tube resonates at every increase of equal length of the tube. At open tube this length must be half the wave length.
 

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