What Is the Frequency of Oscillation in a Series RLC Circuit?

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SUMMARY

The frequency of oscillation in a series RLC circuit with a resistance of 100 ohms, a capacitor of 0.1 microfarads, and an inductance of 10 millihenries is calculated using the formula f = 1 / (2 * π * √(LC)). This results in a frequency of approximately 159.15 Hz. At resonance, the inductive reactance (Xl) equals the capacitive reactance (Xc), leading to a purely resistive circuit. However, the current at resonance cannot be determined without knowing the voltage (V) applied to the circuit.

PREREQUISITES
  • Understanding of RLC circuit components (resistor, inductor, capacitor)
  • Familiarity with the formula for frequency of oscillation in RLC circuits
  • Knowledge of reactance in AC circuits
  • Basic principles of Ohm's Law
NEXT STEPS
  • Calculate the frequency of oscillation for different RLC circuit configurations
  • Explore the effects of varying resistance on current at resonance
  • Learn about the concept of impedance in RLC circuits
  • Investigate the role of voltage in determining current in AC circuits
USEFUL FOR

Electrical engineering students, hobbyists working with RLC circuits, and anyone studying oscillatory behavior in electrical systems.

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Homework Statement


A resistance of 100 ohm is connected in series with capacitor 0.1 microF and an inductance 10 mH. find the frequency of oscillation and value of current at resonance?


Homework Equations



f= 1 / 2*pi*sqrt(LC)

The Attempt at a Solution


i think the formula i use for frequency of oscillation is correct. but how do i find the value of current at resonance. will it be I= V/R. because it resonance Xl=Xc so they cancel each other so the circuit will be purely resistance. kindly suggest.
 
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You are correct in your thinking, however the problem as you stated it doesn't say what V is, so you cannot find the current.
 

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