What Is the Frictional Force Acting on a 16 kg Mass on an Incline?

[kmikias]

Hi all i have a question that i couldn't figure out here is the question.


1.A block is at rest on the incline. The coefficients of static and kinetic friction are μs = 0.7 and μk = 0.59, respectively. The acceleration of gravity is 9.8 m/s2 .What is the frictional force acting on the 16 kg mass? Answer in units of N

here is what i did.

First i try to find the normal force.which is F = M * a

which equall to N - cos33 * mg = ma
N - cos 33 * 16 (9.8) = 0 because acceleration is 0.
then N = 131.50

After i found normal force I use static friction = μ * N

which is 0.7 * 131.50 = 92.052.

Ok then my answer is still wrong so i need some help .

thank you.

 

[Kurdt]

What is the component of force down the incline? And therefore how much frictional force opposes it.