What is the Fundamental Frequency in the Fourier Series of cos4t + sin8t?

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SUMMARY

The fundamental frequency ω0 in the Fourier Series of the function x(t) = cos(4t) + sin(8t) is determined by the individual frequencies of the components. In this case, the coefficients are A8 = 1 and B4 = 1, with all other coefficients being zero. The optimal choice for ω0 is 1, which simplifies the expressions and maintains the periodicity of the series at 2π. This choice allows for a clearer representation of the Fourier Series.

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helderdias
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Hi everyone,

So I was trying to calcule the Fourier Series of x(t) = cos4t + sin8t, but I'm a little bit confused. What would be ω0 in this case since I have a combination of two functions with different frequencies?

Thank you in advance.
 
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I don't know what you mean by \omega_0 here. A Fourier series is a sum
\sum_{n=0}^\infty A_n sin(nt)+ B_n cos(nt)
Here, obviously A_8= 1, B_4= 1 and all other coefficients are 0.
 
I thought the series was the sum of An*cos(nw0t) + Bn*sen(nw0t)
 
Typically Fourier series are presented as HallsofIvy posted. However, there's no reason not to include a frequency term \omega_0. This can simplify some expressions, and you are free to choose any \omega_0 you like. It's important to remember that any choice of \omega_0 changes the periodicity to \frac{2\pi}{\omega_0}.

For your example, it's clearly best to choose \omega_0=1
 

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