- #1
intenzxboi
- 98
- 0
the general solution for ye^x dy/dx = [e^-y ] + [ e^ -2x-y ]is:
so i tried to see if this was a homogenous equation but it is not.
next i tried to simplify and got:
y e^y dy= (1+e^-2x) dx / e^x
so i tried to see if this was a homogenous equation but it is not.
next i tried to simplify and got:
y e^y dy= (1+e^-2x) dx / e^x