What is the heat of a system when it expands by 0.67 m^3?

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SUMMARY

The heat of a system that expands by 0.67 m3 at a constant pressure of 105 kPa, with a decrease in internal energy of 1710 J, can be calculated using the first law of thermodynamics. The equation used is ΔU = Q - W, where W is the work done by the system, calculated as W = PΔV. By substituting the values, the correct heat (Q) can be determined as Q = ΔU + W.

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Homework Statement


A system expands by 0.67 m^3 at a constant pressure of 105 kPa. Find the heat of the system if its internal energy decreases by 1710J.


Homework Equations


Since P=constant:
deltaU=Q-W
W=PdeltaV


The Attempt at a Solution


I tried plugging in the numbers to the equation for W and then plugging that value into the first equation to solve for U, but I didn't get the correct answer and I'm not sure where I went wrong.
 
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Nobody will know where you went wrong if you don't say what you plugged into where and what came out of that process.
 
sorry, but while I was typing my process just now I realized what went wrong. Thank you!
 

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