What is the Integral of 1/{x-(1-x^2)0.5} and How Can It Be Simplified?

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SUMMARY

The integral of the function \(\int\frac{dx}{x-\sqrt{1-x^2}}\) can be simplified using trigonometric substitution, specifically \(x = \sin(u)\), followed by the Weierstrass substitution \(v = \tan(u/2)\). This method, while lengthy, provides a pathway to solve the integral. Attempts to use partial fraction decomposition on the term \(\frac{\sqrt{1-x^2}}{2x^2-1}\) are invalid, as the numerator is not a polynomial. The discussion highlights the complexity of the integral and confirms that simplification requires advanced techniques.

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Homework Statement


\int\frac{dx}{x-\sqrt{1-x^2}}


Homework Equations



The Attempt at a Solution



i try to simplify it by multiplying \frac{x+\sqrt{1-x^2}}{x+\sqrt{1-x^2}},becoming =\frac{x+\sqrt{1-x^2}}{2x^2-1}
=\int{\frac{x}{2x^2-1}+\frac{\sqrt{1-x^2}}{2x^2-1}}dx

ps:
a.Can i partial fraction the last term to \frac{A}{x-\frac{1}{\sqrt{2}}}+\frac{B}{x+\frac{1}{\sqrt{2}}}??
b.i try to integrate by using wolfram alpha online ,but the steps is incredibly long..
does it exist any other simpler way??
 

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I checked W-A, and they did it the same way I would have: Begin with a trig substitution like x=sin(u), then use the Weierstrass substitution: v=tan(u/2). It will be long and difficult, but it's possible.
 
haleycomet2 said:
a.Can i partial fraction the last term to \frac{A}{x-\frac{1}{\sqrt{2}}}+\frac{B}{x+\frac{1}{\sqrt{2}}}??
No, because both the numerator and denominator of the original fraction must be polynomials, and in
\frac{\sqrt{1-x^2}}{2x^2-1}
the numerator is not a polynomial.
 
o,i see.Thanks a lot:smile:
 

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