im having problem integrating the equation dydx=y^2/x^2 and also dydx=3*y^2/x
Apr 5, 2010 #1 math_trouble 5 0 Main Question or Discussion Point im having problem integrating the equation dydx=y^2/x^2 and also dydx=3*y^2/x
Main Question or Discussion Point im having problem integrating the equation dydx=y^2/x^2 and also dydx=3*y^2/x
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Apr 5, 2010 #2 g_edgar 607 0 I'm assuming they should be dy/dx=y^2/x^2 and dy/dx=3*y^2/x . Your differential equations textbook should discuss "separation of variables" near the very beginning.
I'm assuming they should be dy/dx=y^2/x^2 and dy/dx=3*y^2/x . Your differential equations textbook should discuss "separation of variables" near the very beginning.
Apr 9, 2010 #3 StalkerM 6 0 This can be rewritten in this way: y'=y^2/x^2 with x different from zero. y'/y^2=1/x^2 using chain rule: d/dx[-1/y]=d/dx[-(1/x)+C] consequentely: 1/y=(1/x)-C y=1/[(1/x)+C]
This can be rewritten in this way: y'=y^2/x^2 with x different from zero. y'/y^2=1/x^2 using chain rule: d/dx[-1/y]=d/dx[-(1/x)+C] consequentely: 1/y=(1/x)-C y=1/[(1/x)+C]