- #1

- 5

- 0

im having problem integrating the equation

dydx=y^2/x^2

and also

dydx=3*y^2/x

dydx=y^2/x^2

and also

dydx=3*y^2/x

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- Thread starter math_trouble
- Start date

- #1

- 5

- 0

im having problem integrating the equation

dydx=y^2/x^2

and also

dydx=3*y^2/x

dydx=y^2/x^2

and also

dydx=3*y^2/x

- #2

- 607

- 0

and dy/dx=3*y^2/x .

Your differential equations textbook should discuss "separation of variables" near the very beginning.

- #3

- 6

- 0

y'=y^2/x^2 with x different from zero.

y'/y^2=1/x^2

using chain rule:

d/dx[-1/y]=d/dx[-(1/x)+C]

consequentely:

1/y=(1/x)-C

y=1/[(1/x)+C]

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