What is the interior of this triangular region on the x-y plane?

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SUMMARY

The interior of the triangular region on the x-y plane is defined by the vertices (0,0), (0,1), and (1,0). The area of interest is constrained by the inequalities 0 < x < y < 1. This region includes all points where the x-coordinate is less than the y-coordinate, effectively forming a right triangle in the first quadrant of the Cartesian plane.

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nhrock3
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my area is
0<x<y<1

i don't know how to draw it on x y plane
 
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It's the interior of the triangular region defined by (0,0), (0,1), and (1,0). Every point in this region is such that x < y.
 

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