What is the Interval of Convergence for \sum x^n/4^n*ln(n) using the Ratio Test?

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Homework Help Overview

The discussion revolves around determining the interval of convergence for the series \(\sum \frac{x^n}{4^n \ln(n)}\) using the Ratio Test. Participants are exploring the implications of the test's results and the nature of the series involved.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants are discussing the application of the Ratio Test and its inconclusive result, questioning the interpretation of the test's outcome. There is also clarification on the series' formulation and its components.

Discussion Status

The discussion is ongoing, with participants clarifying the series' expression and exploring the implications of the Ratio Test results. There is no explicit consensus yet, but some guidance on the nature of the series and the test's application is being provided.

Contextual Notes

Participants are addressing potential confusion regarding the series' terms, particularly the placement of \(\ln(n)\) in the denominator and the absence of additional factors in the series. The inconclusiveness of the Ratio Test is a central point of discussion.

Sabricd
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[tex]\sum[/tex] x^n/4^n*ln(n)

I have applied the Ratio Test and I got 1 and I am trying to find the interval of convergence. However, by the Ratio Test, the answer is inconclusive. It does not prove whether it is convergent or divergent. Any ideas?

Thanks!
 
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Sabricd said:
[tex]\sum[/tex] x^n/4^n*ln(n)

I have applied the Ratio Test and I got 1 and I am trying to find the interval of convergence. However, by the Ratio Test, the answer is inconclusive. It does not prove whether it is convergent or divergent. Any ideas?

Thanks!

Just checking... Is this the sum you're working with?
[tex]\sum \frac{x^n}{4^n}n~ln(n)[/tex]
 
Hello,

Nope, it is x^n/(4^n * Ln(n))

Thank you, I think I am just having trouble applying the Ratio Test.
 
There is no extra n, and the Ln(n) goes in the denominator :)
 
So the sum is: [tex]\sum_{n=0}^{\infty}{\frac{x^{n}}{4^{n}\ln(n)}}[/tex]. Could you show how you reached your conclusions? The ratio of consecutive x-coefficients is not one. Even if it were one, that would not mean that the result is inconclusive (it would mean that the sum is a constant multiple of the geometric series which has a radius of convergence of 1).
 
Last edited:

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