What is the Interval of Convergence for the Series x^n/(n3^n)?

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SUMMARY

The discussion focuses on determining the radius and interval of convergence for the series \(\sum_{n=0}^\infty \frac{x^n}{n3^n}\). The ratio test was applied, resulting in the limit \(L = |x/3|\). This indicates that the series converges for \(-3 < x < 3\). However, it is essential to check the endpoints separately, as the ratio test is inconclusive when \(L = 1\).

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Homework Statement


Find the radius of convergence and the interval of convergence for
<br /> \sum_{n=0}^\infty \frac{x^n}{n3^n}<br /> <br />

Homework Equations


The Attempt at a Solution


Ok, so I first applied the ratio test.
<br /> \lim_{n\rightarrow\infty}<br /> <br /> |<br /> \frac{x^{n+1}}{(n+1)3^(n+1)} /<br /> \frac{x^n}{n3^n}<br /> |<br />

After some cancellations I got

<br /> L = |x/3|<br /> <br />Does this mean that the interval of convergence is from -3<x<3 ?
 
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Yes.
 
You have to check the endpoints of your interval separately to see if the series converges there since the ratio test doesn't give any information when the limit is 1
 

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