What is the Inverse of a Cubic Function?

[tg43fly]

Homework Statement

Find the inverse of f(x)=ln(x^3-3x^2+3x-1)

Homework Equations

n/a

The Attempt at a Solution

y=ln(x^3-3x^2+3x-1)
x=ln(y^3-y^2+3y-1)
e^x=(y^3-y^2+3y-1)

i looked around for inverse of cubic functions and i found a monster of a formula:
http://www.math.vanderbilt.edu/~schectex/courses/cubic/
i really hope i missed something to find the inverse

 

[D H]

y=ln(x^3-3x^2+3x-1)
x=ln(y^3-y^2+3y-1)
e^x=(y^3-y^2+3y-1)

You dropped a very important factor of three in going from y=ln(x^3-3x^2+3x-1) to x=ln(y^3-y^2+3y-1).

i looked around for inverse of cubic functions and i found a monster of a formula:
http://www.math.vanderbilt.edu/~schectex/courses/cubic/
i really hope i missed something to find the inverse

Those factors of three should suggest something. Hint:Look at Pascal's triangle.

 

[tg43fly]

whoops
$$y=ln(x^3-3x^2+3x-1)$$
$$y=ln(x-1)^3$$
$$x=ln(y-1^3)^3$$
$$e^x=(y-1)^3$$
$$y=e^x/3+1$$
ty for the hint