What is the limit of (xcsc2x)/(cos5x) as x approaches 0?

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SUMMARY

The limit of (xcsc2x)/(cos5x) as x approaches 0 can be evaluated using the fundamental limit lim as x approaches 0 (sinx)/x = 1. By rewriting the expression as (x(1/sin2x))/(cos5x), one can apply the limit properties. Specifically, the limit lim as x approaches 0 of (2x)/(sin(2x)) equals 1, leading to the conclusion that the overall limit evaluates to 0, since cos(5x) approaches 1 as x approaches 0.

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Homework Statement



lim as x-> 0

(xcsc2x)/(cos5x)


Homework Equations



lim as x-> 0 (sinx)/x = 1


The Attempt at a Solution



(x(1/sin2x)) / (cos5x)

Not sure what I am supposed to do here! Thanks
:)
 
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Firstly, if this is true:

[tex]\lim_{x\rightarrow0} \frac{sin(x)}{x} = 1[/tex]

Then can you figure out what this limit is?

[tex]\lim_{x\rightarrow0} \frac{x}{sin(x)}[/tex]

And then if you use 2x instead of x, this limit should be just as easy:

[tex]\lim_{x\rightarrow0} \frac{2x}{sin(2x)}[/tex]
 

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