What is the magnetic field strength?

Click For Summary
SUMMARY

The discussion focuses on calculating the magnetic field strength (B) for a circular loop of wire with a diameter of 14.2 cm, carrying a current of 3.10 A, which experiences a torque of 0.135 m N. The torque on the loop is derived from the forces acting on the wire segments in the magnetic field. The relevant formula for torque (τ) in this context is τ = F * (L/2), where F is the force on the wire segments, calculated using F = I * L * B. By integrating the contributions from all segments of the circular loop, one can derive the magnetic field strength required for this specific scenario.

PREREQUISITES
  • Understanding of magnetic fields and forces
  • Familiarity with the concept of torque in physics
  • Basic knowledge of calculus for integration
  • Experience with circular loops in electromagnetism
NEXT STEPS
  • Study the derivation of torque for circular loops in magnetic fields
  • Learn about the integration of forces in circular geometries
  • Explore the application of Ampère's Law in magnetic field calculations
  • Review the principles of electromagnetism related to current-carrying conductors
USEFUL FOR

Students and educators in physics, particularly those focusing on electromagnetism, as well as engineers working with magnetic field applications in electrical devices.

IHave
Messages
21
Reaction score
0

Homework Statement


A 14.2 cm - diameter circular loop of wire is placed with the plane of the loop parallel to the uniform magnetic field between the pole pieces of a large magnet. When 3.10 A flows in the coil, the torque on it is 0.135 m N. What is the magnetic field strength?

2. Homework Equations ;3. The Attempt at a Solution
Okay, I know that I need to find the value for B, the magnetic field; and that there are a number of equations that I can use. However, I am a bit confused, since torque is given; I know that it will be used in some way.

Any help is welcome!
 
Physics news on Phys.org
That is a tough one! Unless you happen to have a formula for the torque on a circular coil in a magnetic field.

I can explain how to do it for a square coil, which should give you some understanding of your problem. A square coil will have four pieces of wire of length L, two of which are parallel to the B field and don't have a force on them. The formula for the force on the other two is F =I*L*B (see http://hyperphysics.phy-astr.gsu.edu/hbase/magnetic/magfor.html#c2). This force F will be perpendicular to both the wire and the B field, and it will be in opposite directions on the two wires so they will try to rotate the loop of wire. The torque for this rotation will be F*L/2 for each of the forces because the force acts distance L/2 from the center of rotation.

If you happen to know calculus, you can think of your circular loop of wire as having an infinite number of segments, each of which has a component dL perpendicular to B. So you can figure out the torque for each of the segments and integrate to get the whole torque. Once you have the formula for Torque due to B, you can solve it for B to do your particular problem.
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 37 ·
2
Replies
37
Views
4K
Replies
4
Views
1K
Replies
49
Views
6K
  • · Replies 5 ·
Replies
5
Views
1K
Replies
4
Views
2K
Replies
16
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
14
Views
3K