What is the Magnitude of Betty's Force for Equilibrium?

AI Thread Summary
The discussion revolves around determining the magnitude of Betty's force (FB) for equilibrium when Charles pulls with a force (FC) of 188 N. The key challenge is identifying the angle at which FB must act to balance the horizontal components of the forces involved. One participant highlights that FB has no horizontal component, suggesting that the angle must be adjusted to ensure the horizontal components of FC and another force (A) are equal and opposite. This realization leads to a clearer understanding of the problem. The conversation emphasizes the importance of analyzing force components to achieve equilibrium.
J-dizzal
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Homework Statement


FC of magnitude 188 N. Note that the direction of FC is not given. What is the magnitude of Betty's force FB if Charles pulls in (a) the direction drawn in the picture or (b) the other possible direction for equilibrium

Homework Equations


ΣF=0[/B]

The Attempt at a Solution


20150623_181903_zpsqwl2uqe2.jpg

Im having trouble with part b) of the question. I don't know what other possiblities there are.
 
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I can't see any of your images. Are they embedded or linked?
 
phinds said:
I can't see any of your images. Are they embedded or linked?

updated
 
B has no horizontal component so you need to find at which angle (other than the one you originally found) the horizontal component of C is exactly opposite to the horizontal component of A. Such an angle is guaranteed to exist (think of the graph of cosine).
 
americanforest said:
B has no horizontal component so you need to find at which angle (other than the one you originally found) the horizontal component of C is exactly opposite to the horizontal component of A. Such an angle is guaranteed to exist (think of the graph of cosine).
oh its so obvious now thanks
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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