What is the Magnitude of Betty's Force for Equilibrium?

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Homework Help Overview

The problem involves determining the magnitude of Betty's force for equilibrium, given a force FC of 188 N with an unspecified direction. The original poster expresses confusion regarding the possible directions for Betty's force in relation to Charles's force.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the implications of the direction of force FC and how it affects the equilibrium condition. The original poster questions the other possibilities for Betty's force. Some participants suggest considering angles and components of the forces involved.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some guidance has been offered regarding the relationship between the horizontal components of the forces, but no consensus has been reached.

Contextual Notes

There is a mention of missing images that may be relevant to the problem setup, which could affect the understanding of the forces involved.

J-dizzal
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Homework Statement


FC of magnitude 188 N. Note that the direction of FC is not given. What is the magnitude of Betty's force FB if Charles pulls in (a) the direction drawn in the picture or (b) the other possible direction for equilibrium

Homework Equations


ΣF=0[/B]

The Attempt at a Solution


20150623_181903_zpsqwl2uqe2.jpg

Im having trouble with part b) of the question. I don't know what other possiblities there are.
 
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I can't see any of your images. Are they embedded or linked?
 
phinds said:
I can't see any of your images. Are they embedded or linked?

updated
 
B has no horizontal component so you need to find at which angle (other than the one you originally found) the horizontal component of C is exactly opposite to the horizontal component of A. Such an angle is guaranteed to exist (think of the graph of cosine).
 
americanforest said:
B has no horizontal component so you need to find at which angle (other than the one you originally found) the horizontal component of C is exactly opposite to the horizontal component of A. Such an angle is guaranteed to exist (think of the graph of cosine).
oh its so obvious now thanks
 

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