What is the magnitude of Electric Field at r=R/2

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SUMMARY

The magnitude of the electric field at a distance r=R/2 from a uniformly charged insulating sphere is calculated using Gauss's law. The correct formula is E=k(4Q/R^2), where k is Coulomb's constant and Q is the total charge enclosed. The confusion arises from the interpretation of the Gaussian surface and the charge distribution within the sphere. It is essential to clarify whether the charge is uniformly distributed over the surface or throughout the volume of the sphere to apply Gauss's law correctly.

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  • Coulomb's Law
  • Gauss's Law
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  • Knowledge of charge distribution types (surface vs. volume)
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  • Explore the concept of Gaussian surfaces and their significance in electrostatics
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jaydnul
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Homework Statement


The first question asks: What is the electric field when the radius of a sphere is R. For this first question I put E=k\frac{Q}{R^2} and got the question correct.

The second question simply states: What is the electric field at r=R/2. I used Coulomb's law, Gauss' law, and common sense and every time got: E=k\frac{4Q}{R^2} but there are no choices that match my answer.

Also there are no choices of E=\frac{Q}{ε_0πR^2}

Am I doing something wrong?
 
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Hello.

It will help if you state the problem with all the given information. For example, I am guessing that the sphere carries electric charge and that there are no other charges present. If the sphere does carry charge, how is that charge distributed? Is it uniformly spread over the surface of the sphere? Or is it uniformly spread throughout the volume of the sphere? Or spread nonuniformly?

It would also help if you would show how you got your answer. Otherwise, we cannot tell if you are doing something wrong.
 
It's a uniformly charged insulating sphere. Asks for the magnitude of electric field on the surface of the sphere. That's all it says.

So I did:
E*4π(\frac{R}{2})^2=\frac{Q_{encl}}{ε_0}
Which simplifies to:
E=k\frac{4Q}{R^2}
Right?
 
Is the charge present only on the surface?
What is your gaussian surface and what charge does it enclose?
 
That's literally everything the problem states...
 
Assuming its a uniform volume charge density-
What is your gaussian surface? What charge does it enclose?
Hint: Find the charge density for second part.
 
I thought the Gaussian surface was the surface of the sphere?

Charge density would be:
S=Eε_0
And the charge it encloses would be Q
 
You need to read up on Gaussian surface...try this http://maxwell.ucdavis.edu/~electro/flux/gaussian_surf.html orhttp://www.phy.duke.edu/~schol/phy152/faqs/faq4/node5.html
Note that for symmetric surfaces it has to pass through the point in question if you want the electric flux there and hence find the field.
Also charge density is given by Q/V where Q is charge and V the Volume.
 

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