What is the magnitude of the acceleration of cylinder's com?

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SUMMARY

The discussion focuses on calculating the magnitude of the acceleration of a uniform solid cylinder's center of mass when subjected to a constant horizontal force of 18 N. The cylinder has a mass of 19 kg and a radius of 0.11 m. Participants suggest using torque and the parallel axis theorem to eliminate frictional forces in the calculations. The moment of inertia for the cylinder is established as I = 3/2 M R^2, which is crucial for determining the net torque and subsequently the acceleration.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with torque and moment of inertia
  • Knowledge of the parallel axis theorem
  • Basic principles of rotational dynamics
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  • Calculate the net torque acting on the cylinder using the correct forces
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Students studying physics, particularly those focusing on mechanics, as well as educators seeking to clarify concepts related to rotational dynamics and torque.

JessicaHelena
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Homework Statement


In the figure below, a constant horizontal force
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app of magnitude 18 N is applied to a uniform solid cylinder by fishing line wrapped around the cylinder. The mass of the cylinder is 19 kg, its radius is 0.11 m, and the cylinder rolls smoothly on the horizontal surface.
(a) What is the magnitude of the acceleration of the center of mass of the cylinder?

Homework Equations

The Attempt at a Solution



I'm confused... I feel like I could use torque — I could set the bottom point as the origin, and then tau_net = 18 x 2 x 0.11 + F_cm x 0.11.
However, I couldn't really get further than that and I am really confused. Could someone help me?
 

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Taking torque about the bottom point is a convenient way of eliminating
the frictional force.
Are you familiar with the parallel axis theorem?
You can also apply Newton's equations about the center of mass
to eliminate the frictional force.
 
@J Hann — what's the parallel axis theorem?
 
JessicaHelena said:
@J Hann — what's the parallel axis theorem?
The moment of inertia I of a body about any axis is equal to the moment of inertia
I CM of the body about a parallel axis through its center of mass plus the mass M of the
body times the square of the perpendicular distance L between the axes:
I = Icm + M L^2.
For a cylinder about an edge I = 1/2 M R^2 + M R^2 = 3/2 M R^2
 
JessicaHelena said:
tau_net = 18 x 2 x 0.11 + F_cm x 0.11.

Taking the torque around the contact point was a very good idea. (Why?) However, your equation for the net torque is wrong. How many forces are there acting on the cylinder? And how many of those produce a torque about the contact point?
 

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