What is the magnitude of the electric field

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Homework Help Overview

The problem involves calculating the magnitude of the electric field generated by two point charges, q1 and q2, located on the x-axis. The specific point of interest for the electric field calculation is at coordinates (0.506 m, 0.506 m).

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss how to approach the calculation of the electric field, including the need to determine distances from the charges to the point of interest. There are questions about the geometric relationships and the use of trigonometric functions.

Discussion Status

Some participants have suggested methods for calculating the electric field vectors based on distances and components, while others are clarifying the relationships between the coordinates and the charges. There is ongoing exploration of how to resolve the electric field into its components and the overall magnitude.

Contextual Notes

Participants are considering the implications of the coordinates provided and the need to calculate distances accurately. There is a focus on ensuring that the correct distances are used for each charge in the electric field calculations.

xswtxoj
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Homework Statement



Two electric charges, q1 = +21.3 nC and q2 = +11.0 nC, are located on the x-axis at x
= 0 m and x = 1.00 m, respectively. What is the magnitude of the electric field at the
point x = 0.506 m, y = 0.506 m?
 
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How would you think to approach the problem?
 
21.3+11.0 /1 = .506/.506 ?
 
Based on what?
 
They want you to find the E-field vector at .506,.506.

First calculate the |E1| and |E2| based on the geometric distance to both charges.

Then separate those vectors - they are vectors - into their components.

Then add the x-components and y components separately.

Happily they only want the magnitude of the E-field - |E| - so just use Pythagoras to figure the |E| of the resulting vector.
 
there's no angle though, so it would be .506 sin____ and .506cos___ or is it 90 or 180 degrees
 
xswtxoj said:
there's no angle though, so it would be .506 sin____ and .506cos___ or is it 90 or 180 degrees

You have the coordinates of the point.

and you know - or should know that a2 + b2 = c2

So ... figure it out.
 
.506 sq + .506 sq = 574.69 then sq root = .715,
 
xswtxoj said:
.506 sq + .506 sq = 574.69 then sq root = .715,

It is .715 but your intermediate result is nonsense.

So that's the r for 1 charge.

Now figure the r for the other.
 
  • #10
21.3 sq + 11 sq= 574.7 equals 23.97 after sq rt, then take the 2 r's and add them up and tan y/x?
 
  • #11
We're looking at distances, not charges.
 
  • #12
would it be : E1= ke q1/ r sq? then E2= ke q2/r sq but how would the 2nd r be found would the x= 0, and 1 or 1, 0.506 since it for q2?
 
  • #13
They want you to find the distance from 1,0 to .506,.506 for the second charge. That triangle then is .494,.506.
 
  • #14
once i get r, i solve for e, then once i get both e's do i add them up or leave it as 2 separate answers?
 
  • #15
xswtxoj said:
once i get r, i solve for e, then once i get both e's do i add them up or leave it as 2 separate answers?

Once you get the |E| (magnitude of E) then you must resolve them into their x,y components and add the components - being careful of the signs - and then determine the magnitude of the result.

They want the magnitude of the Total E field at that point.
 

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