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n_h0987
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Homework Statement
Three point charges, q1 = -4.19 nC, q2 = 5.41 nC and q3 = 2.51 nC are aligned along the x-axis as shown in the figure below.
[URL]http://imgur.com/RaRML[/URL]
Assume that L1 = 0.496 m and L2 = 0.816 m. Calculate the electric field at the position (0, 2.02).
Homework Equations
E = kq/r^2
The Attempt at a Solution
Horizontal electric field = Ex = k(-4.19*10^-9)cos76/2.08^2 + k(2.51*10^-9)cos68/2.18^2 = -0.3276 N/C
Vertical electric field = Ey = k(-4.19*10^-9)sin76/2.08^2 + k(5.41*10^-9)/2.02^2 + k(2.51*10^-9)sin68/2.18^2 = 7.88 N/C
Net field = square root of Ex^2 + Ey^2 = 7.88 N/C
Please help! :(
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