What is the Mass Density of Air at 1 atm and -50°C?

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SUMMARY

The mass density of air at 1 atm and -50°C can be calculated using the ideal gas law. The average molecular mass of air is 29 u, which corresponds to 1.75 x 10^25 molecules. The correct density calculation yields approximately 1.2 kg/m³, significantly lower than the erroneous value of 1.96 x 10^44 kg/m³ initially computed. Proper unit conversion and understanding of molecular mass are crucial for accurate density calculations.

PREREQUISITES
  • Understanding of the ideal gas law (PV = nRT)
  • Knowledge of molecular mass and its significance in calculations
  • Familiarity with unit conversions, particularly in chemistry
  • Basic grasp of statistical mechanics concepts
NEXT STEPS
  • Study the ideal gas law and its applications in real-world scenarios
  • Learn about molecular mass and its conversion to grams per mole
  • Explore unit conversion techniques in physical chemistry
  • Investigate statistical mechanics and its relation to gas behavior
USEFUL FOR

Students in chemistry or physics, researchers in atmospheric science, and professionals involved in gas density calculations will benefit from this discussion.

jmb07
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Average molecular mass of air is 29 u. What is the mass density of air at 1 atm and -50 degrees celsius??

This is what i have so far...

V=(NkT)/P so V= [(29u)(1.38E^-23)(-50 + 273)]/ 1 = 8.9 x10^-20

The mass is equal to 29u x (6.022 x 10^23) =1.75 x 10^25

density =m/v so = 1.96 x 10^44...and that is wayyyy off! The correct answer is like around 1, 2, or 3...i need some help. What am i doing wrong?
 
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Try carrying your units through your equations. What does it mean to have a molecular mass of 29?
 
uh...i know i could try to convert the 29u to (number of atoms)...but i don't have any molecular weight
 
29u tells you something about the relationship between mass (which is connected to density) and the number of moles (which is connected to the ideal gas law that you're using).
 

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