How Far Will a Box Slide with Initial Speed and Friction?

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SUMMARY

The discussion centers on calculating the distance a box will slide after being pushed with an initial speed of 3.9 m/s, given a coefficient of kinetic friction of 0.23. It is established that the mass of the box is not necessary for this calculation, as it cancels out in the equations. The deceleration of the box can be determined using the formula for frictional force, resulting in an acceleration of -0.23g. This leads to a definitive method for calculating the distance traveled using the kinematic equations.

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richk_83
A box is given a push so that it slides across the floor. How far will it go, given that the coefficient of kinetic friction is 0.23 and the push imparts an initial speed of 3.9 m/s?
Could someone help, to me it is missing a part but that is the entire question
 
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Something is missing. What is the mass of the box? You need this in order to calculate the deaccelation of the box. Then you multiply the kinetic coefficient by the mass of the box. This will give you the force acting against the motion of the box. Then use "F=ma" to calculate that deaccelation. I hope this helps you.
Terence
 
Nothing is missing. The mass cancels. Acceleration = -0.23g
 

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