What is the Mass of the Uniform Disk Used as a Cam on a Vertical Shaft?

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SUMMARY

The mass of a uniform disk used as a cam on a vertical shaft with a diameter of 38 cm and a moment of inertia of 7.5 x 10^-3 kg*m/s is calculated using the parallel axis theorem. The calculation shows that the mass is approximately 0.1385 kg, which aligns closely with the provided options, specifically option c (0.14 kg). The angular velocity of 70 rpm is not directly needed for the mass calculation but is relevant for understanding the disk's rotational dynamics.

PREREQUISITES
  • Understanding of moment of inertia and its calculation
  • Familiarity with the parallel axis theorem
  • Basic knowledge of rotational motion and angular velocity
  • Ability to perform unit conversions (e.g., cm to meters)
NEXT STEPS
  • Study the parallel axis theorem in detail
  • Learn about moment of inertia for different shapes
  • Explore the relationship between angular velocity and rotational dynamics
  • Investigate applications of cams in mechanical systems
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Mechanical engineers, physics students, and anyone involved in the design and analysis of rotating systems will benefit from this discussion.

Soaring Crane
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A uniform disk is attached at the rim to a vertical shaft and is used as a cam. The disc has a diameter of 38 cm. The moment of inertia of the disk about the axis of the shaft is 7.5*10^-3 kg*m/s. The shaft rotates uniformly about its axis at 70 rpm. The mass of the disc is closest to:

a.0.12 kg
b. 0.092 kg
c. 0.14 kg
d. 0.18
e.0.16 kg

I don’t know why the angular velocity is given. This is what I managed to do:

Using parallel axis theorem,

I_p = I_cm + M*d^2 = 0.5*M*r^2 + M*r^2 = 1.5*M*r^2

M = (I_p)/(1.5*r^2) = (0.0075 kg*m/s)/(1.5*.19 cm^2) = 0.1385 kg

Thanks.
 
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Is this the right track?

Thanks again.
 
Looks good to me.
 

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